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Therefore, h=0.220 cm is the water level rise in case of pine.ĥ) You are swimming in the indoor pool at the Holiday Inn Moon-Base in the year 2041. Weight of Idaho pine=d*V=530* (4/3)*π*(5/100)^3=0.277 kgĢ77 grams of wood is equivalent to 277 grams of water which is also 277 cm3 of water Therefore, h= 0.416 cm is the water level rise in case of steelĪ) Idaho white pine has a density of 530 kg/m3 so it displaces water equal to its weight. Volume of steel sphere=Volume of water in the bucket= (4/3)*π*5^3=523.598 〖cm〗^3 Volume of water in the bucket= π*r^2*h= π*〖20〗^2*(h) 〖cm〗^3 where h is water level Therefore, water level rise (volume rise in a half-filled bucket) is equal to the volume of the steel sphere. How much does the water level go up if you drop a steel sphere of radius 5cm into the bucket? How much does the water level go up if you drop in a 5cm radius sphere made out of Idaho white pine?Ī) Steel has a density of 8,050 kg/m3 so it will be completely immersed in water. The bucket is round with radius of 20cm, and it is 50cm tall.
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The greater density of the ocean water is due to presence of dissolved salts that adds to the existing upward force by water molecules.Ĥ) A straight sided bucket is half full of water. The greater density of ocean compared to that of fresh water causes a greater buoyant force application on the body of the swimmer. Sea water has a density of about 1025 kg/m^3 >Fresh water has a density of about 1000 kg/m^3
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Need A Unique Essay on "Archimedes’ Principle Lab" ? Use Promo "custom20" And Get 20% Off! Order Nowģ) Explain why the buoyant force is greater if you are swimming in the ocean versus fresh water.